For the following reaction : Na 2 CO 3 + 2HCl 2NaCl + CO 2…

Chemistry Some Basic Concepts of Chemistry The Mole Concept Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 14, 2026

For the following reaction : Na 2 CO 3 + 2HCl 2NaCl + CO 2 + H 2 O

106.0 g of Na 2 CO 3 reacts with 109.5 g of HCl.

Which of the following is/are correct.

The HCl is in excess.

117.0 g of NaCl is formed.

The volume of CO 2 produced at NTP is 22.4 L.

None of these

Text Solution

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The correct answer is:

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(a,b,c)

(Mw of Na 2 CO 3 = 106, Mw of HCl = 36.5, Mw of NaCl = 58.5)

Moles of Na 2 CO 3 = = 1.0 mol

Moles of HCl = = 3.0 mol

Since for 1 mol of Na 2 CO 3 , 2 mol of HCl is required.

So, HCl is in excess (3 – 2) = 1.0 mol

Therefore, Na 2 CO 3 is the limiting quantity.

Weight of NaCl formed = (1.0 mol Na 2 CO 3 ) = 1 × 58.5 = 117.0 g NaCl

1 mol of Na 2 CO 3 = 1 mol of CO 2 = 22.4 L at NTP

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